(x^2-4)^2+(x^2-4)-6=0

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Solution for (x^2-4)^2+(x^2-4)-6=0 equation: 



(x^2-4)^2+(x^2-4)-6=0

We get rid of parentheses

x^2+(x^2-4)^2-4-6=0

We add all the numbers together, and all the variables

x^2+(x^2-4)^2-10=0

We move all terms containing x to the left, all other terms to the right

x^2+(x^2-4)^2=10

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